Division A and B in a school have 20 students each. One student is to be selected from each division. What is the probability that Rahul in division .A will be selected, if 2 students are selected out of 40 students ?
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The answer is (C(1,1) × C(20,1) ) /(C(20,1) ×C(20,1)) = 1/20
I hope it helps.
I hope it helps.
subhadeepmom:
Probability of selecting rahul feom A is c(1,1)/c(20,1)=1/20
Probability of selecting rahul feom A is c(1,1)/c(20,1)=1/20 and probability of select 2 student out of 40 is 2/40 ao answer is 1/20*2/40=1/400=0.0025 is this correct?
No bro Please revise your concept book once
you are quite deviated
Answered by
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1/20 or 2/40 so the probability is low here
Probability of selecting rahul feom A is c(1,1)/c(20,1)=1/20 and probability of select 2 student out of 40 is 2/40 ao answer is 1/20*2/40=1/400=0.0025 is this correct?
yes
but more correct is 1/20
But see the last line it says if 2 students are selected out of 40 students
1/20 is the probability of selecting rahul from 20 student but question is about selecting 2 students
ha to phir
2students out of 40
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