Question

Division of polynomials. (6x3+8x2)y÷2x​

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

(((6 • (x3)) - 23x2) - 4x) + 2

STEP

2

:

Equation at the end of step

2

:

(((2•3x3) - 23x2) - 4x) + 2

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

6x3 - 8x2 - 4x + 2 =

2 • (3x3 - 4x2 - 2x + 1)

Checking for a perfect cube :

4.2 3x3 - 4x2 - 2x + 1 is not a perfect cube

Trying to factor by pulling out :

4.3 Factoring: 3x3 - 4x2 - 2x + 1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -2x + 1

Group 2: -4x2 + 3x3

Pull out from each group separately :

Group 1: (-2x + 1) • (1) = (2x - 1) • (-1)

Group 2: (3x - 4) • (x2)