division p(x)=x^3+3x^2-2 and g(x)=x-2 solve the division?
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Hello friend
Your answer is given in the attachment
I hope it will help you a lot
Thanks
Your answer is given in the attachment
I hope it will help you a lot
Thanks
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Answered by
0
p(x)= x^3+3x^2-2
g(x)= x-2
by the remainder theorem,
x-2=0
x= 2
p(2)= 2^3+3*2^2-2
= 8+12-2
= 20-2
= 18
g(x)= x-2
by the remainder theorem,
x-2=0
x= 2
p(2)= 2^3+3*2^2-2
= 8+12-2
= 20-2
= 18
shahbaz29:
thanx
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