Question

Division (using factorise) x² - 17x + 16 by x - 16​

Answer 1

Answer:

$\huge{\underline{\underline{\tt{\blue(.Question}}}}$

$Division (using factorise) x² - 17x + 16 by x - 16$

$\huge{\underline{\underline{\tt{\blueſ.Answer}}}}$

$\huge{\underline{\underline{\tt{\blueſ.(x-1)}}}}$

Step-by-step explanation:

$On factorising, x² - 17x + 16$

$x²-17x+16$

$x²-x-16x+16$

$x(x-1)-16(x-1)$

$(x-16)(x-1)$

$Now, On division$

$(x-16)(x-1)/(x-16)$

$\huge{\underline{\underline{\tt{\blueſ.(x-1)}}}}$

Answer 2

$\bf \large \bold{ \underline{\underline \pink{Given :}}}$

$\bf \small {Polynomial \: {x}^{2} - 17x + 16 \: and \: x - 16}$

$\bf \large{ \underline {\underline \orange{Required \: answer : }}}$

$\bf \small{To \: divide \: the \: given \: polynomials} \\ \bf \small{ using \: factor isation}$

$\bf \large {\underline {\underline {\red{Solution : }}}}$

$\bf \small{Factorise \: \: {x}^{2} - 17x + 16}$

$\implies \sf{ {x}^{2} - 17x + 16}$

$\implies \sf{ {x}^{2} - 16x - x + 16}$

$\implies \sf{x(x - 16) - (x - 16)}$

$\implies \sf{(x - 16)(x - 1)}$

$\bf{Dividing \: (x - 16)(x - 1) \: by \: x - 16} \\ \bf{we \: get,}$

$\implies \sf{ \frac{(x - 16)(x - 1)}{(x - 16)} } = x - 1$

$\bf \small \blue {Hence, \: (x - 1) \: is \: the \: solution.}$