Divit has a total of ₹6000 currency notes of denomination ₹50, ₹100, and ₹200. The proportion of the number of these notes is 2:3:4. How many notes of each denomination does he have?
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Answer:
Let
No. of currency notes of Rs 50 = 3x
No. of currency notes of Rs 20 = 5x
No. of currency notes of Rs 10 = 25 - (3x+5x) = 25 - 8x
Amount made by Rs 50 notes = 50 × 3x = 150x
Amount made by Rs 20 notes = 20 × 5x = 100x
Amount made by Rs 10 notes = 10 × (25 - 8x) = 250 - 80x
Total money = 590
⇒ 150x + 100x + 250 - 80x = 590
⇒ 170x = 340
⇒ x = 2
Denominations:
Rs 50 = 3 × 2 = 6
Rs 20 = 5 × 2 = 10
Rs 10 = (25 - 8 × 2) = 9
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