Question

diviya deposided 8000 rupees in a bank, which gives 10% interest compounded annually. after 2 years, withdraw 5000 rupees. after one more year, how much would she have in her account​

Answer 1

Answer

• The total amount will be ₹10648

Explanation

Given

• Diviya deposited ₹8000
• Interest = 10%
• Time = 2years

To Find

• Amount she would have after 2 years

Solution

Amount is given by,

→ A = P(1+R/100)ⁿ

• A = Amount
• P = Principal
• R = Interest
• n = Time

✭ Amount will be

→ A = P(1+R/100)ⁿ

• A = ?
• P = 8000
• R = 10%
• n = 2 years

→ A = 8000(1+10/100)³

→ A = 8000({100+10}/100)³

→ A = 8000(110/100)³

→ A = 8000(11/10)³

→ A = 8000(1331/1000)

→ A = 8×1331

→ A = 10648

Answer 2

Answer:

✯ Given :-

• Diviya deposited Rs 8000 in a bank, which gives 10% interest compounded annually after 2 years, withdraw RS 5000.

✯ To Find :-

• After one year how much rupees would she have in her account.

✯ Formula Used :-

$\boxed{\bold{\small{✮\: Simple\: Interest\: =\: \dfrac{P\: ×\: r\: ×\: t}{100}}}}$

$\boxed{\bold{\small{✮\: Amount\: =\: Simple\: Interest\: +\: Principal}}}$

✯ Solution :-

⋆ Given :

• Principal (P) = Rs 8000
• Rate of Interest (r%) = 10%
• Time (t) = 2 years

➣ According to the question by using the formula we get,

⇒ S.I = $\dfrac{8000 × 10 × 2}{100}$

⇒ S.I = $\dfrac{16000}{100}$

⇒ S.I = $\sf\dfrac{\cancel{16000}}{\cancel{100}}$

➥ S.I = 160

➢ Again, we have to find the value of amount,

↦ A = 160 + 8000

➠ Amount = Rs 8160

$\therefore$ The total money she have in her account is Rs 8160 .

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