Question

Divled 1/3x^2 by -2/9x
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Answer 1

Answer:

$(\frac{1}{3x} )^{2}$ ÷ $(\frac{-2}{9x} )$

$(\frac{1}{9x^{2}} )$ × $(\frac{-9x}{2} )$  = $\frac{-1}{2x}$

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