Question

Divya bought potatoes for Rs. ${\bold20{\bold{\frac{1}{2}}}}$ and tomatoes for Rs. ${\bold40{\bold{\frac{1}{5}}}$. How much money did she receive back, did she gave the shopkepper a note of Rs. 100?

Answer 1

♣ Qᴜᴇꜱᴛɪᴏɴ :

Divya bought potatoes for Rs.$\sf{20\dfrac{1}{2}}$  and tomatoes for Rs.$\sf{40\dfrac{1}{5}}$ . How much money did she receive back, did she gave the shopkepper a note of Rs. 100?

♣ ɢɪᴠᴇɴ :

Cost of Potatoes = Rs.$\sf{20\dfrac{1}{2}}$

Cost of Tomatoes = Rs.$\sf{40\dfrac{1}{5}}$

Money given to shopkeeper = Rs. 100

♣ ᴛᴏ ꜰɪɴᴅ :

Money Recieved Back

♣ ᴀɴꜱᴡᴇʀ :

Money Recieved Back = Rs. 39.3

♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

Total cost = Cost of Potatoes + Cost of Tomatoes

Total cost = Rs.$\sf{20\dfrac{1}{2}}$  + Rs.$\sf{40\dfrac{1}{5}}$

______________________

→ Convert mixed fractions into improper fraction !!

$\sf{20\dfrac{1}{2}} = \sf{\dfrac{20\times 2+1}{2}}= \bf{\dfrac{41}{2}}$

$\sf{40\dfrac{1}{5}} = \sf{\dfrac{40\times 5+1}{5}}= \bf{\dfrac{201}{5}}$

______________________

Total cost = Rs.$\sf{20\dfrac{1}{2}}$  + Rs.$\sf{40\dfrac{1}{5}}$

Total cost = Rs.$\sf{\dfrac{41}{2}}$  + Rs.$\sf{\dfrac{201}{5}}$

L.C.M  of 2 and 5 = 10

Total cost = Rs.$\sf{\dfrac{41\times 5}{2\times 5}}$  + Rs.$\sf{\dfrac{201\times 2}{5\times 2}}$

Total cost = Rs.$\sf{\dfrac{205}{10}}$  + Rs.$\sf{\dfrac{402}{10}}$

Total cost = Rs.$\sf{\dfrac{205+402}{10}}$

Total cost = Rs.$\sf{\dfrac{607}{10}}$

Total cost = Rs. $\sf{60.7}$

______________________

Money Recieved Back = Total money - Total Cost

Money Recieved Back = Rs. 100 - Rs. 60.7

Money Recieved Back = Rs. 39.3

Answer 2

→ Correct question :-

• Divya bought potatoes for Rs.${\bold20{\bold{\frac{1}{2}}}}$  and tomatoes for Rs.${\bold40{\bold{\frac{1}{5}}}}$. How much money did she receive back, if she gave the shopkeeper a note of Rs. 100?

→ Given :-

• Divya bought potatoes for Rs. ${\bold20{\bold{\frac{1}{2}}}}$

• Divya bought tomatoes for Rs. ${\bold40{\bold{\frac{1}{5}}}}$

Step-by-step explanation:

→ To Find :-

• How much money did she receive back,  if she gave the shopkeeper   a note of Rs. 100?

→ Solution :-

• Cost of potatoes = Rs.${\bold20{\bold{\frac{1}{2}}}}$
• covert into improper fraction = ${\bold{\frac{20~x~2~+~1}{2}}}}$ = ${\bold{\frac{41}{2}}}}$

• Cost of tomatoes = Rs. ${\bold40{\bold{\frac{1}{5}}}}$  
• convert into improper fraction = ${\bold{\frac{40~x~5~+~1}{5}}}}$ = ${\bold{\fbox{\frac{201}{5}]}}}}$${\bold{\frac{201}{5} }}}}$

• LCM of 2,5 = 10
• ${\boxed{\bold{\frac{205}{10}}}} ~~~+$  ${\boxed{\bold{\frac{402}{10}}}}$  
• ${\boxed{\bold=~{\bold{\frac{607}{10}}}}}$
• If she gave the shopkeeper Rs. 100 so,
• ${\boxed{\bold{\frac{100}{1} }}}}~~-~~$   ${\boxed{\bold{\frac{607}{10} }}}$  
• LCM of 1,10 = 10

• ${\boxed{\bold{\frac{1000}{10} }}}}~~-~~$   ${\boxed{\bold{\frac{607}{10} }}}$

• ${\boxed{\bold{\frac{393}{10}}}}}$

• convert into mixed fraction = ${\boxed{\bold3\bold9\bold{\frac{3}{10}}}$

• She receive back, in mixed fraction =  ${\boxed{\bold3\bold9\bold{\frac{3}{10}}}$

• In numbers = 39.30

${\huge{\fbox{\fbox{\bold{\ Hence ~ stated}}}$