Math, asked by aahanashaikh3369, 1 day ago

Divya makes two cylindrical models, A and B, of diameter 21 cm each for an art project. The height of model B is 2 more than the height of model A. She wants to paint the curved surface of the models. She paints a total of 396 square metres of model A.If the cost to paint is 0.25/sq. m, what is the total cost to paint both the models? (Use for π=22/7)

Answers

Answered by manibharathip1993
3

Answer:

Answer : 231

Step-by-step explanation:

Attachments:
Answered by Dhruv4886
0

The total cost to paint two cylinders is Rs. 231  

Given:

Divya makes 2 cylindrical models, A and B, of a diameter of 21 cm each for an art project. The height of model B is 2 more than the height of model A. She paints a total of 396 square metres of model A.

The cost to paint is 0.25/sq. m  

To find:

What is the total cost to paint both models?  

Solution:

Diameter of both cylinders, d = 21 m  

Radius of the cylinder, r = 21 cm/2 = 10.5 m  

Let 'H' be the height of the cylinder

From the data,

She paints a total of 396 square metres of model A  

Using the formula,

The curved surface area of a cylinder = 2πrH,

Area of the model, A =  2(22/7)(10.5)H,

A =  2(22)(1.5)h = 66H  

As we know the area of model A = 396 m²  

=> 396 m² =  66H  

=> H = 6 m

The height of model B is 2 more than the height of model A

Height of the model B = 6 m + 2 m = 8 m

Area of model B = 2(22/7)(10.5)(8) = 528 m²  

The cost to paint is 0.25/sq. m  

The total cost to paint two cylinders = [0.25 × 396] × [0.25 × 528]

= Rs. 99 + Rs. 132 = Rs. 231  

Therefore,

The total cost to paint two cylinders is Rs. 231  

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