Divya makes two cylindrical models, A and B, of diameter 21 cm each for an art project. The height of model B is 2 more than the height of model A. She wants to paint the curved surface of the models. She paints a total of 396 square metres of model A.If the cost to paint is 0.25/sq. m, what is the total cost to paint both the models? (Use for π=22/7)
Answers
Answer:
Answer : 231
Step-by-step explanation:
The total cost to paint two cylinders is Rs. 231
Given:
Divya makes 2 cylindrical models, A and B, of a diameter of 21 cm each for an art project. The height of model B is 2 more than the height of model A. She paints a total of 396 square metres of model A.
The cost to paint is 0.25/sq. m
To find:
What is the total cost to paint both models?
Solution:
Diameter of both cylinders, d = 21 m
Radius of the cylinder, r = 21 cm/2 = 10.5 m
Let 'H' be the height of the cylinder
From the data,
She paints a total of 396 square metres of model A
Using the formula,
The curved surface area of a cylinder = 2πrH,
Area of the model, A = 2(22/7)(10.5)H,
A = 2(22)(1.5)h = 66H
As we know the area of model A = 396 m²
=> 396 m² = 66H
=> H = 6 m
The height of model B is 2 more than the height of model A
Height of the model B = 6 m + 2 m = 8 m
Area of model B = 2(22/7)(10.5)(8) = 528 m²
The cost to paint is 0.25/sq. m
The total cost to paint two cylinders = [0.25 × 396] × [0.25 × 528]
= Rs. 99 + Rs. 132 = Rs. 231
Therefore,
The total cost to paint two cylinders is Rs. 231
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