Question

Divya's father's age is 3times of her age.After 12 years her father's age is 2 times of her age.Find their present ages?​

Answer 1

Answer:

divya's present age=12 years

her father's present age=36years

Step-by-step explanation:

Let divyas present age be x

let her father's age =y

by data,

y=3x------(1)

y+12=2(x+12)

•: y=2x+24-12=2x+12-------(2)

from (1) and (2) we get,

3x=2x+12

•: x=12

•: y=3(12)=36

Answer 2

$\huge\sf{\underline{\underline{Solution:}}}$

Divya's present age is 12 years and Divya's father's present age is 36 years.

Solution:

It is given that,

Divya's father's age is 3 times of her age.

Thus;

Let the present age of Divya be xyears

and the present age of her father's age be 3x years.

Also,

Divya's age after 12 years will be ;

(x + 12) years.

And ,

Divya's father's age after 12 years will be ; (3x + 12) years.

According to the question;

After 12 years Divya's father is two times of her age.

ie;

=> 3x + 12 = 2(x + 12)

=> 3x + 12 = 2x + 24

=> 3x - 2x = 24 - 12

=> x = 12

Thus,

Divya's present age

= x years

= 12 years

And,

Divya's father's present age

= 3x years

= 3•12 years

= 36 years

Hence,

The present ages of Divya and herfather are 12 years and 36 yearsrespectively.