Question

Divya started from her house at 6:30 AM and travelled some distance till 7:30 AM. After covering 75% of that distance further, she found that she had covered 75% of total distance. Find the fraction of the total distance travelled by her by 8:30 AM. ​

Answer 1

Step-by-step explanation:

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b;

int multiplication;

clrscr();

printf("Enter the first number");

scanf("%d", &a);

printf("Enter the second number");

scanf("%d", &b);

multiplication = a*b;

printf("The Total is %d", multiplication);

getchar();

}

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Answer 2

Answer:

6/7

Step-by-step explanation:

Let the distance covered by Divya is 1st hour be 4x km.

so the speed of the Divya is 4x kmph.

Now after covering 75% of that distance further the distance covered in this case

= 4x * 75%

= 4x * 75/100

= 4x * 3/4

= 3x km.

Now according to question

4x + 3x = 75% of the total distance

i.e 7x = 3/4 of total distance

Total distance = 28x / 3 km.

Distance travelled till 8:30 AM = 4x * 2 = 8x

Fraction of the total distance covered = 8x / (28x / 3)

=24x / 28x

= 6 / 7