Question

Divya took a loan of 19500 with si for as many years as the rate of interest. if she paid 4875 as I at end of loan period , what is the loan period​

Answer 1

Answer:

P = 19500

SI = 4875

Let R = T = X

A/q,

4875 = 195*x²

x² = 25

x = 5 = Rate = Time

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Answer 2

Answer:

5

$4875 = \frac{19500 \times t \times t}{100} \: \: (r = t) \\ \\ \frac{4875}{195} = {t}^{2} \\ t = \sqrt{25 } \\ t = 5 \: years$