Divyaraj started walking in east and walked 12 m.
Now he turned south and walked 4 m and turned to
his left and walked 3 m. Now he turned south and
walked 7 m. Now to his left and walked 7 m. Now he
turned south and walked 8 m, then to west and
walked 5 m. Now to his left walking 3 m and finally
turned right and walked 3 m. Find the distance from
where he started walking.
Answers
Answer:
may be it helps u☺️
Step-by-step explanation:
22m Is the answer for this question
Answer:
distance between his initial and final points is 26.07 m
Step-by-step explanation:
given, divyaraj first walked 12 m towards east then he turned south and walked 4 m, then he walked 3 m towards east.
he walked 7 m to south and 7 m to east. again he walked 8 m towards south and then 5 m to west.
he then turned south and walked 3 m and finally walked 3 m towards west
to find: distance between his initial and final points
refer to the image attached
total distance he walked towards east (AE) = 12+ 3+ 7 = 22 m
total distance he walked towards west (CD) = 5+ 3 = 8m
distance AB = 4+ 7+ 8+ 3 = 22 m
distance BC = 22 - 8 = 14m
to find distance AC
ABC forms right triangle, so we can use pythagoras theorem
hypotenuse² = base²+ height ²
⇒ AC² = AB²+ BC²
⇒ AC² = 22² + 14²
AC² = 484 + 196 = 680
AC = √680 = 26.07 m
thus, distance between his initial and final points is 26.07 m
