Economy, asked by aliabass4444, 4 months ago

DJ LeMahieu of the Colorado Rockies had the highest batting average in the 2016 Major League Baseball season. His
average was .348. So assume the probability of getting a hit is .348 for each time he batted. In a particular game, assume
he batted three times.

a. This is an example of what type of probability?

b. What is the probability of getting three hits in a particular game?

c. What is the probability of not getting any hits in a game?

d. What is the probability of getting at least one hit?​

Answers

Answered by amitnrw
3

Given : DJ LeMahieu of the Colorado Rockies had the highest batting average in the 2016 Major League Baseball season.

His  average was .348

So assume the probability of getting a hit is .348 for each time he batted. In a particular game,

he batted three times

To Find : a. This is an example of what type of probability?

b. What is the probability of getting three hits in a particular game?

c. What is the probability of not getting any hits in a game?

d. What is the probability of getting at least one hit?​

Solution:

This is an example of   Normal Distribution

probability of hitting p = 0.348

probability of not hitting q =  1 - p = 1 - 0.348  = 0.652

P(x) = ⁿCₓpˣqⁿ⁻ˣ

n = 3

probability of getting three hits in a particular game  = P(3)

=  ³C₃(0.348)³(0.652)³⁻³

= (0.348)³

= 0.04214

probability of not getting any hits in a game

P(0)

= ³C₀(0.348)⁰(0.652)³⁻⁰

=  0.2772

probability of getting at least one hit

= 1 - P(0)

= 0.7228

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Answered by Itscutekanak
5

Answer:

This is an example of   Normal Distribution

probability of hitting p = 0.348

probability of not hitting q =  1 - p = 1 - 0.348  = 0.652

P(x) = ⁿCₓpˣqⁿ⁻ˣ

n = 3

probability of getting three hits in a particular game  = P(3)

=  ³C₃(0.348)³(0.652)³⁻³

= (0.348)³

= 0.04214

probability of not getting any hits in a game

P(0)

= ³C₀(0.348)⁰(0.652)³⁻⁰

=  0.2772

probability of getting at least one hit

= 1 - P(0)

= 0.7228

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