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25. The radius of a sphere is measured as (2.1 +0.5) cm. Its surface area with error limits is
a) (55.4 25.4) cm
b) (52.4 22.4) cm?
c)(55.4 26.4) cm?
c) (52.4 25.4) cm
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Answer:
c) 55.4 ± 26.4cm²
Explanation:
Sphere is a perfect round geometrical object in three-dimensional space that is the surface of a completely round ball.
Radius of sphere S = (2.1 +0.5) cm (Given)
Surface area of sphere = S = 4πr²
Therefore,
= 4π (2.1)²
= 55.4cm²
= ΔS/S = 2Δr/r→ ΔS = 2Δr/rS
= ΔS = 2×0.5×55.4/2.1
=26.4cm²
= S =55.4 ± 26.4cm²
Therefore, the surface area with error limits is 55.4 ± 26.4cm²
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