Question

djacent angles.
:) Find two numbers whose ratio is 6:4 and their difference is 10.​

Answer 1

Correct Question:-

Find two numbers whose ratio is 6:4 and their difference is 10.

Given:-

• Ratio of numbers = 6:4
• Difference = 10

To Find:-

• Numbers

Solution:-

Put x in the ratio,

• First number = 6x
• Second number = 4x

According to question,

$\large { \rm \longmapsto \: \: \: \: \: \: \: \:6x - 4x = 10}$

$\large { \rm \longmapsto \: \: \: \: \: \: \: \:2x = 10}$

$\large { \rm \longmapsto \: \: \: \: \: \: \: \:x = \cancel \frac{10}{2} }$

$\large { \rm \longmapsto \: \: \: \: \: \: \: \:x = \bf{ \boxed{ \green{ 5}}}}$

Now,

• First number = 6x = $\boxed{ \red{ \mathfrak{ \large{ \underline{ \purple{30}}}}}}$
• Second number = 4x = $\boxed{ \large{ \mathfrak{ \red { \underline{ \purple{20}}}}}}$

Hence,

• The numbers are 30 and 20 respectively.

Answer 2

$\:\:\:\: \Large \underline {\sf{Given\::}}$

➟ Ratio of two numbers is 6:4

➟ Their difference is 10

$\:\:\:\: \Large \underline {\sf{To\:Find\::}}$

➟ Numbers

$\:\:\:\: \Large \underline {\sf{Solution\::}}$

• Let the unknown entity be "x"

→ So the numbers become 6x and 4x

$\:\:\:\: \bigstar \: \large \underline {\sf{According\:to\:the\:question\::}}$

$: \implies\sf 6x\:-\:4x\:=\:10$

$: \implies\sf 2x\:=\:10$

$: \implies\sf x\:=\: \cancel \dfrac{10}{2}$

$\large\underline{\boxed{\sf{Value\:of\:x\:is\:5}}}$

$\:\:\:\: \large \underline {\sf{Numbers\:are\::}}$

1. 6x = 6(5) = 30
2. 4x = 4(5) = 20

$\:\:\:\: \large \underline{\boxed{\sf{Numbers\:are\:30\:and\:20}}}$

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