DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 11.24). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL.
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Solution:
In right angled triangle BAC, AB = 5 cm, BC = 13 cm and AC = 12 cm.
Area of triangle BAC = 1/2 × Base × Height
= 1/2 × 5 cm × 12 cm
= 30 cm2
Area of triangle ABC = 1/2 × Base × Height
Now BC = 13 cm
30 cm2 = 1/2 × 13 cm × AD
AD = (30 cm2 × 2) / 13 cm
AD = 60 cm2 / 13 cm
AD = 4.61 cm
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