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13. An object with an initial velocity of 4 m/s moves along a straight axis under constant
acceleration. Three second later, its velocity is 14 m/s. How far did it travel during
this
time?
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Answer:
27 m
Explanation:
V= U + at
14= 4+a(3)
10 = 3a
a = 10/3 m/sec^2
V^2 - U^2 = 2aS
14^2 -4^2 = 2(10/3) S
180 = 20/3 S
S = 27 m
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