Question

DLEMS FOR
PRACTICE
1. Two point charges are placed on x-axis; a 2uc charge at x = 10 cm and -luc at x =
40 cm. Calculate the potential at point x = 100 cm.
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Answer 1

Answer:

First you have to find the potential due to first charge and potential due to second charge at x=100cm and add them algebrically.

V_{1}=q/4\pi \epsilon _{0}r

V_{1}=2*10^{-6}*9*10^{9}/90*10^{-2}

V_{1}=18*10^{3}/9*10^{-1}

V_{1}=2*10^{4}V

Similarly find out V2

You will get

V_{2}=-1.5*10^{4}V

Net potential at x=100cm is

V=V1+V2

V=0.5*104V

V=5*103V