Question

do 2 question please ......................​

Answer 1

Answer:

The triplets are 37, 35 and 12

Step-by-step explanation:

As we know 2m, $m^{2}$ + 1 and $m^{2}$- 1 form a Pythagorean triplet for any number, m > 1.

Let's assume

$m^{2}$+1=37

Then, $m^{2}$=36

And M=6

Now put the value of M

2M = 12

$m^{2}$+1=37

$m^{2}$-1=35

The triplets are 37, 35 and 12

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Answer 2

$\color{green}\large\underline{\underline{Hello...}}$

$\color{blue}\large\underline{\underline{Answer:}}$

1. First four two digit square numbers are :

• 16
• 25
• 36
• 49

2. The Pythagorean triplet whose greatest number is 37 is :

• ${(6)}^{2} + {(1)}^{2} = 37$

$\color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}}$