Do 26 if u get then pls tell me
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HERE IS YOURS SOLUTION;
◆ Explanation:
sinθ×sinθ(1+cosθ)×sinθ+(1+cosθ)×(1+cosθ)sinθ×(1+cosθ)
=sin2θ+1+2cosθ+cos2θsinθ×(1+cosθ)
◆ Using the pythagorean identity cos2θ+sin2θ=1
=2+2cosθsinθ×(1+cosθ)
=2(1+cosθ)sinθ×(1+cosθ)
=2sinθ
◆ Now recall that 1sinθ=Cosecθ
=2Cosecθ
★ So, the anwer is 2Cosecθ ★
HOPE IT HELPS
◆ Explanation:
sinθ×sinθ(1+cosθ)×sinθ+(1+cosθ)×(1+cosθ)sinθ×(1+cosθ)
=sin2θ+1+2cosθ+cos2θsinθ×(1+cosθ)
◆ Using the pythagorean identity cos2θ+sin2θ=1
=2+2cosθsinθ×(1+cosθ)
=2(1+cosθ)sinθ×(1+cosθ)
=2sinθ
◆ Now recall that 1sinθ=Cosecθ
=2Cosecθ
★ So, the anwer is 2Cosecθ ★
HOPE IT HELPS
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