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s = 1000m
V(0) = 0, g = 9.8 m/s2
∴s = v(0)t + (1/2)gt2
1000 = 0+(1/2)×9.8×t2
t2= (2000/9.8) or t= (100/7)s
Horizontal velocity of the
body=Velocity of the aircraft
Or v = 500 km/h = (500×1000)/(60×60)=1250/9 m/s
Therefore, distance between the body and the target= v × t
= (1250×100)/(9×7)
= 1984 m= 1.984 Km.
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V(0) = 0, g = 9.8 m/s2
∴s = v(0)t + (1/2)gt2
1000 = 0+(1/2)×9.8×t2
t2= (2000/9.8) or t= (100/7)s
Horizontal velocity of the
body=Velocity of the aircraft
Or v = 500 km/h = (500×1000)/(60×60)=1250/9 m/s
Therefore, distance between the body and the target= v × t
= (1250×100)/(9×7)
= 1984 m= 1.984 Km.
IF YOU LIKE MY ANSWER ADD TO BRAINLIST AND FOLLOW ME.
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