Question

do
. A bullet hits a wall with a velocity of 20 m/s and
penetrates it up to a distance of 5 cm. Find the
deceleration of the bullet in the wall.​

Answer 1

Answer:

declaration of the bullet in the wall is 4m/s

Answer 2

Answer:

u= 20 m/s

v= 0

s = 5 cm = 0.05 m

from 3rd equation,

v² -u² = 2as

⇒0 - (20)² = 2×0.05×a

⇒0.1 a = - 400

⇒a = - 4000 m/s²

deceleration will be - 4000 m/s²