Physics, asked by iramfairy, 15 days ago

Do any one please fast

Attachments:

Answers

Answered by ravindramandal06432
0

Answer:

Three Equations of Motion are v = u + at; s = ut + (1/2) at² and v² = u² + 2as and these can be derived with the help of velocity time graphs using definition acceleration.

Answered by BrainlSrijan1
0

Ans. 48

Equations of motion by graphical method. Consider an object moving along a straight line with initial velocity u and uniform acceleration a. ... 8.19, its velocity-time graph is straight line. Here OA = ED = u, OC = EB = v and OE = t = AD.

Ans. 49

Given that a body is travelling at uniform acceleration along a straight line with initial velocity u and final velocity v at time t.

Acceleration a = v-u / t

at = v - u

v = u + at ---------------------------- (1)

Distance s = velocity * time

s = (u+v)/2 * t

s = (u + u + at) /2 * t

s = (2u/2 + at/2)t

s = ut +1/2*at^2 -------------------- (2)

Squaring both sides of equation 1, we get:

v^2 = (u+at)^2

= u^2 + a^2t^2 + 2uat

= u^2 + 2a (ut +1/2 at^2)

v^2 = u^2 + 2as ---------------------- (3)

Thus we have 3 equations of motion.

Attachments:
Similar questions