Do any two and solve by any method
whoever does this will receive brainliest
Answers
Answer:
16.. Let Salim and his daughter's age be x and y yr respectively. Now, by first condition Two years ago, Salim was thrice as old as his daughter. i.e.,
and by second condition, six years later. Salim will be four year older than twice her ago.
On subtracting Eq. (i) from Eq. (ii), we get
Put the value of y in Eq. (ii), we get
Hence, Salim and his daughter's age are 38 yr and 14 yr, respectively.
Step-by-step explanation:
18...
Let the two numbers be x and y.
As per condition 1, i.e., Two numbers are in the ratio 5:6.
The equation becomes,
y
x
=
6
5
∴6x−5y=0 ..........(1)
As per condition 2, If 8 is subtracted from each of the numbers the ratio is 4:5.
The equation becomes,
y−8
x−8
=
5
4
∴5x−4y=8 ...........(2)
Equation (1) can be written as x=
6
5y
Substituting x=
6
5y
in (2) we get,
y=48
Re substituting y=48 in (1) we get,
x=40
Hence Numbers are 40,48.
Please mark as brainliest....
Answer:
18. Let the number be 5x and 6x respectively.
After subtracting 8 , the first no. = 5x - 8
After subtracting 8 , the second no.= 6x-8
Therefore, the ratio of the no. = 5x - 8/6x - 8
This is given to be 4:5
Therefore, 5x-8/6x-8 = 4/5
cross multiplication gives 5(5x-8)=4(6x-8)
Or, 25x - 40 = 24x - 32
Or, 25x-24x = -32+40
Or, x = 8
Therefore, 1st no. = 5x =5×8=40
2nd no.= 6x = 6×8 = 48