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1) An elevator descends into a mine shaft at the rate of 5m/min. if the descent starts from 8m above the ground level, how long will it take to reach 42 km.( means -42 )below the ground level.
Answers
Given : An elevator descends into a mine shaft at the rate of 5m/min.
the descent starts from 8m above the ground level,
To Find : how long will it take to reach 42 m.( means -42 )below the ground level.
Solution:
descent starts from 8m above the ground level,
Hence from + 8
Reaches upto 42 m below the ground
Hence -42 m
Distance covered = | -42 - 8 |
= | - 50|
= 50 m
Speed = 5 m/m
Distance = Speed * time
=> 50 = 5 * time
=> time = 10 sec
elevator will take 10 secs
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