Math, asked by vishwatiwari21105, 1 month ago

Do as directed.
1. Find prime factors of 48.
2. Find two common multiples of 6, 8 and 12.
Uses L.C.M and H.C.F in appropriate conditions.
Solve the following problems.
1. Find H.C.F : 18 and 24
2. Find L.C.M.:27, 36, 54​

Answers

Answered by nikhilbanerjee2008
0

Answer:

1) 2*2*2*2*3

2) 24,48

1) 6

2) 108

Answered by tennetiraj86
3

Step-by-step explanation:

Solutions :-

1) Given number = 48

48 = 1×48

48 = 2×24

48 = 3×16

48 = 4×12

48 = 6×8

48 = 8×6

48 = 12×4

48 = 16×3

48 = 24×2

48 = 48×1

The factors of 48 = 1,2,3,4,6,8,12,16,24,48

The Prime factors of 48 = 2,3

2) Given numbers = 6,8,12

Factors of 6 = 1,2,3,6

Factors of 8 = 1,2,4,8

Factors of 12 = 1,2,3,4,6,12

Common factors of 6,8 and 12 = 1,2

3)

1) Given numbers are 18 and 24

Factors of 18 = 1,2,3,6,9,18

Factors of 24 = 1,2,3,4,6,8,12,24

Common factors of 18 and 24 = 1,2,3,6

Heighest common factor = 6

HCF of 18 and 24 is 6

2) Given numbers are 27,36 and 54

Multiples of 27 = 27,54,81,108,135,162,189,216,...

Multiples of 36 = 36,72,108,144,180,216,...

Multiples of 54 = 54, 108,162,216,...

Common multiples of 27 ,36 and 54 = 108,216,...

Least common multiple = 108

LCM of 27,54 and 36 is 108

Points to know:-

»Every number has infinite number of multiples .

»Every number is a factor of itself.

»1 is the factor of every number.

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