Question

Do as directed:
(a) Find the probability that there will be 5 Sundays in the month of July.
(b) Find the probability that there will be 5 Sundays in the month of June.
(c) What is the probability that a non-leap year contains 53 Sundays?
(d) What is the probability that a leap year contains 53 Sundays? ​

Answer 1

Answer:

Below-

Step-by-step explanation:

(a) Find the probability that there will be 5 Sundays in the month of July.

Ans. 3/7

(b) Find the probability that there will be 5 Sundays in the month of June.

Ans.4 Sundays in four weeks in 4 weeks so your answer is 28

(c) What is the probability that a non-leap year contains 53 Sundays?

Ans The probability of getting 53 Sundays in a non-leap year is 1/7.

Because

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52weeks = 52 x 7 = 364 days

365 - 364 = 1day

in a non-leap year, there will be 52 Sundays and one day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Of these total 7 outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1 / 7.

(d) What is the probability that a leap year contains 53 Sundays? ​

Ans.The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is72.