Question

do by substitution method 3x-5y-4=0and9x=2y+7​

Answer 1

Step-by-step explanation:

3x-5y-4=0 (1)

9x=2y+7 (2)

x=(2y+7)/9 (3)

sub 3 in 1

3(2y+7)/9-5y=4

(2y+7)/3-5y=4

2y+7-15y=12

-13y=5

y=-5/13

sub.y=-5/13 in 3

x=(2y+7)/9

x=(2×-5/13+7)/9

x=(-10/13+7)/9

x=(-10×9+7×13)/13×9

x=(-90+91)/117

x=1/117

Answer 2

Step-by-step explanation:

3x-5y-4=0

9x=2y+7

now

3x-5y=4

9x-2y=7

from 1st equation

3x=4+5y

x=4+5y/3

now put the value of x in eq2

9×(4+5Y÷3)-2Y=7

12+15Y-2Y=7

13Y=7-12

13Y=-5

Y=-5÷13

now put this value of Y in eq 1&2 you will get ur ans