Question

Do help me guysss..... 1) A body is projected vertically upward with velocity 'V'. Find its velocity at half of its maximum velocity. 2) The velocity-Time relation of a particle is given by V=kt, where k=2m/$s^{2}$.Find the distance travelled in first 3 seconds.

Answer 1

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1. ✏️For a body projected up,

Hmax=2gu2

By equation

v2=u2−2gh

Putting, h=2Hmax=4gu2

v2=u2−2gv2=u2−2g4gu2

=u2−2u2

v2=2u2

v=2u

✏️u=kt

dx=kt 

⇒dx=ktdt

or∫0xdx=∫03ktdt

x=k(2t2)03=k(29)=2(29)=9m

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