Question

do in direct method (1) (ab+x²) (ab-x²)​

Answer 1

Step-by-step explanation:

Here is you answer.

ab( {x}^{2} + 1) + x( {a}^{2} + {b}^{2} )ab(x

2

+1)+x(a

2

+b

2

)

◆(ab){x}^{2} + x( {a}^{2} ) + x( {b}^{2} ) + ab(ab)x

2

+x(a

2

)+x(b

2

)+ab

◆ ax(bx + a) + b(bx + a)ax(bx+a)+b(bx+a)

Now taking [bx + a] as common , we get.

◆(ax + b)(bx + a)(ax+b)(bx+a)

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Answer 2

Answer:

we will use the identity (a+b)(a-b)=a^2-b^2

(1)(ab)^2-(x^2)^2

a^2b^2-x^4