do. In the given figure, A
given figure, AB= ACE is a hand on CB
produced.
If Ad is perpendicular to Bo and Ef perpendicator
to AC Prome that A B X EP - ABXEC?
sol.
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Answer:
Given AB=AC
∴∠B=∠C...........(1)
In △ABD and △ECF
∠B=∠C (From 1)
∠ADB=∠EFC=90o [∵AD⊥BC and EF⊥AC,]
∴ By AA Criterion of Similarity, △ABD ∼ △ECF [henceproved]
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