Question

do it...............​

Answer 1

Answer:

${(x + 1)}^{2} = 2(x - 3) \\ = > {x}^{2} + 2 \times x \times 1 + {1}^{2} = 2x - 6 \\ = > {x}^{2} + 2x + 1 = 2x - 6 \\ = > {x}^{2} + 2x + 1 - 2x + 6 = 0 \\ = > {x}^{2} + 7 = 0 \\ = > {x}^{2} = - 7 \\ = > x = \sqrt{ - 7}$

Answer 2

Answer:

(x+1) ²=2(x-3)

x²+2+1=2x-6

x²+3=2x-6

x²+3+6=2x

x²+9=2x

x²-2x+9