Question

do it by Pythagoras theorm

Answer 1

The answers are :-

$\sin(c) = \frac{12}{13} \\ \\ \cos(c) = \frac{5}{13} \\ \\ \tan(c) = \frac{12}{5}$


Please refer the above photograph for the used process.



KEY POINTS TO REMEMBER :-


☸️ Pythagoras Theorem :-
${h}^{2} = {p}^{2} + {b}^{2}$


☸️ Trigonometric ratios of the sides :-
$\sin( \alpha ) = \frac{p}{h} \\ \\ \cos( \alpha ) = \frac{b}{h} \\ \\ \tan( \alpha ) = \frac{p}{b}$



Thanks!

Answer 2

By pythagoras theorem:

BC^2=AC^2+-AB^2

BC^2=13^2-5^2

BC^2=169-25

=BC^2=144

=BC=12

sinC=AB/AC

=12/13

cosC=BC/AC

=5/13

tanC=sinC/cosC

=12/13*13/5

=12/5