Math, asked by thakursreetoma, 7 months ago

do it by shreedharacharya​

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Answered by GETlost0hell
0

Answer:

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(m/n)x^2 +(n/m) = 1-2x

(m/n)x^2 +2x =1-(n/m)

x^2 +2(n/m)x =n/m -n^2/m^2

add (n/m)^2 both side

x^2 +2.(n/m).x +(n/m)^2 =n/m -n^2/m^2+n^2/m^2

(x+n/m)^2 =n/m

take square root ,

x + n/m = +_ √(n/m)

x = -n/m +_√(n/m)

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Answered by Anonymous
33

Answer:

Solve the following quadratic equations by factorization: (m/n)x^2+n/m=1-2x - Sarthaks eConnect | Largest Online Education Community

Now, one of the products must be equal to zero for the whole product to be zero. Hence we equate both the product to zero. In order to find the value of x. Therefore,

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