Question

do it fast..........​

Answer 1

50$\sqrt{3}$

Let AB=75= Height of Pole

and AD be the length of the wire

From △ABD

sin60°=ADAB

⇒

$\sqrt{3}$/2=75/AD

⇒AD=150/$\sqrt{3}$

⇒1.73150    (Take $\sqrt{3}$=1.73)

⇒ 86.6m

Hope this helps you

Please mark as brainliest