Question

do it fast plzzzz....​

Answer 1

$\boxed{\huge{\sf{AnswEr-:}}}$

$\boxed{\blue{\sf{\star{\:The\:other\:side\:of\:triangle\:is= 15 cm }}}}$

$\large{\sf{Given-:}}$

• The hypotenuse of a Right angled triangle is 17 cm .

•One of the remaining two sides is 8cm.

$\large{\sf{To\:Find-:}}$

•Length of other side .

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 8}\put(2.8,.3){\large\bf 15}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\end{picture}$

$\large{\sf{Solution-:}}$

• Let the length of other side of triangle be X cm . ..............(1) .

•$\large{\star{\sf{By \: Applying \:Pythagoras\:Theorem-:}}}$

$\boxed{\blue{\sf{\star{(Hypotenuse)^{2}= (Side_{1} )^{2}+ (Side_{2} )^{2} }}}}$

Here ,

• Hypotenuse = 17 cm.

•Side 1 = 8 cm.

•Side 2 = ??

$\pink{\sf{\rightarrow{(17)^{2}= (8 )^{2}+ (Side_{2} )^{2}}}}$

$\pink{\sf{\rightarrow{289= 64+ (Side_{2} )^{2}}}}$

$\pink{\sf{\rightarrow{289 - 64=(Side_{2} )^{2}}}}$

$\pink{\sf{\rightarrow{225=(Side_{2} )^{2}}}}$

$\pink{\sf{\rightarrow{\sqrt{225}=(Side_{2} )}}}$

$\pink{\sf{\rightarrow{\sqrt{15 cm }= (Side_{2})}}}$

$\boxed{\blue{\sf{\star{Hence,\:The\:other\:side\:of\:triangle\:is= 15 cm }}}}$

_____________________________

$\large{\sf{\star{ More \:To\:Know-:}}}$

•Pythagoras theorem -: It states that in a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides .

•$\boxed{\blue{\sf{\star{(Hypotenuse)^{2}= (Side_{1} )^{2}+ (Side_{2} )^{2} }}}}$

_____________________________

Answer 2

We are given the hypotenuse and the length of one side.

Let the unknown side be x.

By Pythagorean theorem,

a²+b²=c²

So,

8²+x² = 17²

x²=225

x² = 15²

x=15

Thus the length of the other side is 15cm.