Do it na pls kal exam hai friends
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Consider triangles ADP and QPC
<DAP = <CQP (Alternate Interior Angles)
<ADP = <QCP ( || )
AD = CQ (given)
therefore, the two triangles are congruent.
therefore, DP = CP (CPCT) -----(1)
const: drop perpendiculars from A and Q on DC at M and N resp.
again by congruence, we can prove that AM and QN are equal.
therefore, AM = QN -------(2)
As AB is ||el to DC, AM will be the height of the triangle BPC
Or, arΔBPC = 1/2*CP*AM
and arΔDPQ = 1/2*DP*QN
from (1) and(2)
arΔBPC is congruent to ΔDPQ ;)
<DAP = <CQP (Alternate Interior Angles)
<ADP = <QCP ( || )
AD = CQ (given)
therefore, the two triangles are congruent.
therefore, DP = CP (CPCT) -----(1)
const: drop perpendiculars from A and Q on DC at M and N resp.
again by congruence, we can prove that AM and QN are equal.
therefore, AM = QN -------(2)
As AB is ||el to DC, AM will be the height of the triangle BPC
Or, arΔBPC = 1/2*CP*AM
and arΔDPQ = 1/2*DP*QN
from (1) and(2)
arΔBPC is congruent to ΔDPQ ;)
Kajalahuja76418:
Thx
wc
omg than kyou you rock this was a very interesting but hard question.
it wasn't that difficult, I'm in 10th std :)
well i am in 8th so its a bit hard for me
:P
can u do this sum please https://brainly.in/question/2804256
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