Question

do it with explanation​

Answer 1

${\mathfrak{\underline{\green{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{ Charge\: (C) = 2\: coulomb}$

$\:\:\:\:\bullet\:\:\:\sf{ Potential\: difference\: (V) = 12 \:voltage}$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Work\: done \:?}$

${\mathfrak{\underline{\red{\:\:\: Calculation:-\:\:\:}}}}$

☯ As we know that;—

$\bigstar\:\: {\boxed{\sf{ V = \dfrac{J}{C} }}}$

$\sf{Where,}$

$\:\:\:\:\bullet\:\:\:\sf{V = Voltage}$

$\:\:\:\:\bullet\:\:\:\sf{J = Work \:done}$

$\:\:\:\:\bullet\:\:\:\sf{C = Charge}$

☯ Substituting the given values:—

$\dashrightarrow\:\: \sf{ V = \dfrac{J}{C} }$

$\dashrightarrow\:\: \sf{ V \times C = J }$

$\dashrightarrow\:\: \sf{ J = 12 \times 2}$

$\dashrightarrow\:\: \underline{\boxed{\sf{ _{}Work \: Done = 24 \:J^{}}}}$

Answer 2

Work is done in moving a charge of 2 coulomb across two points having a potential difference of 12 volt is 24 joule .