Question

do it with explanation​

Answer 1

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Two \:resistors \:each \:of \:6 \Omega\: and \:4 \Omega \:are\: connected\: in \:series}$

$\:\:\:\:\bullet\:\:\:\sf{Potential \:difference \:(V) = 20\: volts}$

${\mathfrak{\underline{\red{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Potential\: difference}$

$\:\:\:\:\bullet\:\:\:\sf{Current\: through\: the \:circuit}$

${\mathfrak{\underline{\pink{\:\:\: Calculation:-\:\:\:}}}}$

☯ Firstly, let's find net resistance:-

$\dashrightarrow\:\: \sf{ R_{net} = R_1 + R_2............R_n}$

$\dashrightarrow\:\: \sf{R_{net} = 6 \Omega + 4 \Omega }$

$\dashrightarrow\:\: {\boxed{\sf{R_{net} = 10 \Omega }}}$

☯ Now, find the current in the circuit:-

$\dashrightarrow\:\: \sf{ V=IR }$

$\dashrightarrow\:\: \sf{I = \dfrac{V}{R} }$

$\dashrightarrow\:\: \sf{I = \dfrac{\cancel{20}}{\cancel{10}} }$

$\dashrightarrow\:\: {\boxed{\sf{ I = 2 \: A}}}$

• Electric current through circuit is $\bf{2A}$ & potential difference be same i.e., $\bf{20V}$

Answer 2

$\: \: \: \huge\fbox\pink{A}\fbox\blue{n}\fbox\purple{s}\fbox\green{w}\fbox\red{e}\fbox\orange{r}$

❥ let resistance be R and R'

so R = 6 ohm

R' = 4 ohm

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so resistance are connected in series

❥ total resistance = R + R'

=6 + 4 = 10 ohm

❥current = potential difference/ resistance

= 20/10 = 2 ampere(A)

potential across 6 ohm resistor

= I×R

= 2× 6 =12 volt

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