Question

do last sum like 2 sum and 3 and solve last one​

Answer 1

Answer:

${p}^{4} \div {p}^{41} \\ \\ \\ \\ \: = > \frac{ {p}^{4} }{ {p}^{41} } \\ \\ \\ = > {p}^{4 - 41} \\ \\ \\ = > {p}^{ - 37} \\ \\ \\ = > \frac{1}{ {p}^{37} }$

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