Question

Do natural frequency of spring mass system on moon same as on earth

Answer 1

Answer:

yes it is same as on the earth i've given in explaination

Explanation:

fn at moon = fn at earth

For a torsional pendulum, frequency of oscillation (f) is defined as,

f = 1/2π √k/I

Here k is the force constant and I is the rotational inertia of the body.

For moon gʹ = g/6. But the frequency is independent of g. It depends on k and I, which are always constant for a given mass and cord. So the frequency does not change.

For simple pendulum,

f = 1/2π √g/l

Here g is the acceleration due to gravity and l is length of pendulum. For moon gʹ = g/6. So the frequency of oscillation depends up on acceleration due to gravity g. It changes when you take the simple pendulum to moon due to gravitational acceleration and it becomes,

f = 1/2π √g/6l.

For simple block oscillator, frequency of oscillation (f) is defined as,

f = 1/2π √k/m

Here k is the force constant and m is the mass of block.

From the above equation f = 1/2π √k/m, we observed that the frequency of oscillation f is independent of acceleration due to gravity g. Therefore it also does not change.

For physical pendulum, frequency of oscillation (f) is defined as,

f = 1/2π √Mgd/I

Here M is the mass of pendulum, g is the acceleration due to gravity, d is the distance from the pivot to the center of mass and I is the rotational inertia of body.

Since the frequency of oscillation depends up on g, therefore it also changes and it becomes,

f = 1/2π √Mgd/6l

hope that's the answer to the question

thanks

Answer 2

The natural frequency of a spring mass system does not depend on the gravitational acceleration.

f=sqrt(m/K).

Therefore the frequency will be unchanged on moon.

Hope it helps you,

Best of luck.