Question

do no. 10 .. plz plz tomorrow is my exam​

Answer 1

Answer:

this is the perfect solution for this ...if satisfied mark me as the brainliest

Answer 2

Answer:

$3^{x}= 5^{y}=45^{z}$

Let this value be k

$3^{x}=k\\=> 3=k^{1/x}$

Also,

$5=k^{1/y}\\45=k^{1/z}$

We know,

45=9*5=3*3*5

Substituting the above values,

45=$k^{1/x}*k^{1/x}*k^{1/y}$

$k^{1/z}=k^{2/x+1/y}$

Therefore, by laws of Indices,

$\frac{1}{z} = \frac{2}{x}+\frac{1}{y}$

$\frac{1}{z}=\frac{2y+x}{xy}$

Rearranging the terms as,

$x=\frac{2yz}{y-z}$

(Q.E.D.)

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