Question

do no. 8 and 9 please

Answer 1

i)-(-7/5)=7/5
7/5=7/5

Answer 2

8. (i)a=7/5
⇒-a=-7/5
⇒-(-a)=-(-7/5)
⇒-(-a)=7/5      [∵-(-)=+]
⇒-(-a)=a.

    (ii)a=-11/18
⇒-a=-(-11/18)
⇒-a=11/18      [∵-(-)=+]
⇒-(-a)=-11/18
⇒-(-a)=a

9.-(p+q)=(-p)+(-q)
   (i)p=7/8,q=1/7
LHS=-(p+q)=-[(7/8)+(1/7)]
=-[(49+8)/56]
=-(57/56)
RHS=(-p)+(-q)=-(7/8)+(-1/7)
=-7/8-1/7
=(-49-8)/56
=-(57/56)
Therefore,LHS=RHS.

   (ii)p=4/5,q=-3/7
LHS=-(p+q)=-[(4/5)+(-3/7)]
=-[(28-15)/35]
=-(13/35)
RHS=(-p)+(-q)=(-4/5)+(-(-3/7))
=(-4/5)+3/7
=(-28+15)/35
=-(13/35)
Therefore, LHS=RHS.