Math, asked by Anshuman3874, 1 year ago

DO NOT GIVE WRONG ANSWER.

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shadowsabers03: Option (D) is the answer.
shadowsabers03: 11

Answers

Answered by shadowsabers03
4

 4^{61} + 4^{62} + 4^{63} + 4^{64} + 4^{65} \\ \\ = 4^{61 + 0} + 4^{61 + 1} + 4^{61 + 2} + 4^{61 + 3} + 4^{61 + 4} \\ \\ = (4^{61} \times 4^0) + (4^{61} \times 4^1) + (4^{61} \times 4^2) + (4^{61} \times 4^3) + (4^{61} \times 4^4) \\ \\ = (4^{61} \times 1) + (4^{61} \times 4) + (4^{61} \times 16) + (4^{61} \times 64) + (4^{61} \times 256) \\ \\ = 4^{61}(1 + 4 + 16 + 64 + 256) \\ \\ = 4^{61} \times 341 \\ \\


Here, we can find that the sum given in the question is the multiple of 4^61 and 341.


341 can't be divided by 3, 6 and 13. So the sum can't be divided by these numbers.


But 341 can be divided by 11.


341 ÷ 11 = 31


So the sum can be divided by 11.


When the sum is divided by 11, we get 4^61 × 31.


11 is the answer.


Option (D) is the answer.


Hope this is understood by you.


Please mark my answer as the brainliest if this may be helpful.


Thank you. Have a nice day.


#adithyasajeevan


shadowsabers03: Thank you for marking my answer as the brainliest.
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