Question

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if it takes 10 seconds for ball dropped from a plane to hit the ground which is its velocity just before it hits.?​

Answer 1

Answer:

Lets assume, that with “plane” you meen a level surface and not an airplane. And further that “drop” means “start with zero initial velocity. (as opposed to throw)

Then the velocity is given by v=at and near the surface of the earth v = g = 9.81 m/s2

So after 10s v=9.81*10 = 98.1m/s (ignoring airresistance)

With a smooth steel ball this will be quite accurate, a styropor ball on the other hand would be very much slower. PLZ MARK ME AS BRAINLIEST ANSWER

Answer 2

Answer:

Lets assume, that with “plane” you meen a level surface and not an airplane. And further that “drop” means “start with zero initial velocity. (as opposed to throw)

Lets assume, that with “plane” you meen a level surface and not an airplane. And further that “drop” means “start with zero initial velocity. (as opposed to throw)Then the velocity is given by v=at and near the surface of the earth v = g = 9.81 m/s2

Lets assume, that with “plane” you meen a level surface and not an airplane. And further that “drop” means “start with zero initial velocity. (as opposed to throw)Then the velocity is given by v=at and near the surface of the earth v = g = 9.81 m/s2So after 10s v=9.81*10 = 98.1m/s (ignoring airresistance)

Lets assume, that with “plane” you meen a level surface and not an airplane. And further that “drop” means “start with zero initial velocity. (as opposed to throw)Then the velocity is given by v=at and near the surface of the earth v = g = 9.81 m/s2So after 10s v=9.81*10 = 98.1m/s (ignoring airresistance)With a smooth steel ball this will be quite accurate, a styropor ball on the other hand would be very much slower.