Math, asked by rupali8153gmailcom2, 1 year ago

Do not spam his her account will be deleted by me as I am moderator

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Answered by sunilsihag403
0

Answer:

Step-by-step explanation:

Here is the answer budddy

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rupali8153gmailcom2: copy paste
rupali8153gmailcom2: taking screenshot and sending aa
rupali8153gmailcom2: I will not mark ur answer as brainliest
Anonymous: hmmm plz ban my id
Answered by Anonymous
4

In Δ AOP and Δ AOC ,

AO = AO [ Common ]

OP = OC [ Radius ]

AP = AC [ Tangent from a single point ]

Δ AOP ≅ Δ AOC [ S.S.S ]

∠POA = ∠AOC [ c.p.c.t ]

Similarly :

Δ BOC ≅ Δ OQB

∠COB = ∠BOQ [ c.p.c.t ]

Add both c.p.c.t :

∠POA + ∠AOC + ∠COB + ∠BOQ = 180

[ angles on a straight line ]

⇒ 2 ∠POC + 2 ∠COB = 180

⇒ ∠POC + ∠COB = 90

⇒ ∠AOB = 90


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rupali8153gmailcom2: Me too having board exam see my profile
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rupali8153gmailcom2: ok
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