Question

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$the \: sum \: of \: the \: zeroes \: of \\ the \: polynomial \\ p(x) = {x}^{2} 6x + 13 \: is \:$

A. 6
B. -6
C. 11
D. -11



Do not give the answer without solving the question. Solve the question and give the answer.


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Answer 1

Answer:

Given, the polynomial

$\huge {\color{lime}6x ^2−13x+6=0}$

$\small{ \red⇒\pink{6x ^2 −9x−4x+6=0}}$

⇒3x(2x−3)−2(3x−3)=0

⇒(2x−3)(3x−2)=0

∴2x−3=0

$\huge{ \color{cyan}⇒x= \frac{3}{2}}$

• 3x−2=0

$\huge\color{magenta}⇒x= \frac23$

Let,

α=

2

3

β=

3

2

From the polynomial we get, a=6,b=−13,c=6

[A)6 is l•l option]

Step-by-step explanation:

. .•(♬•G1•♬)