Question

Do only the circle ones plz xi.no and x.no​

Answer 1

Answer:

$1) { (\frac{1}{6} + \frac{1}{8} )}^{ - 1} + {( \frac{1}{3} + \frac{1}{2} ) }^{ - 1} \\ { (\frac{4 + 3}{24} )}^{ - 1} + { (\frac{5}{6}) }^{ - 1} \\ { (\frac{7}{24}) }^{ - 1} + { (\frac{5}{6} )}^{ - 1} \\ \frac{24}{7} + \frac{6}{5} = \frac{120 + 42}{35} = \frac{162}{35}$

$2) \: (\frac{1}{1} + \frac{1}{2} + \frac{1}{3} ) \times \frac{1}{4} \\ ( \frac{6 +3 +2}{6} ) \times \frac{1}{4} \\ ( \frac{11}{6} ) \times \frac{1}{4} = \frac{11}{24} \\ hope \: it \: helps \: you...$

Answer 2

x)

$</p><p></p><p>\Rightarrow \quad \left( 6^{-1} + 8^{-1} \right)^{-1} + \left( 3^{-1} + 2^{-1} \right)^{-1} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \left( \frac{1}{6} + \frac{1}{8} \right)^{-1} + \left( \frac{1}{3} + \frac{1}{2} \right)^{-1} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \left( \frac{8 + 6}{48} \right)^{-1} + \left( \frac{2 + 3}{6} \right)^{-1} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \left( \frac{14}{48} \right)^{-1} + \left( \frac{5}{6} \right)^{-1} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{48}{14} + \frac{6}{5} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{ 48(5) + 6(14) }{ 70 }</p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{ 240 + 84 }{70}</p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{ 324 }{ 70 }</p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{162}{35} </p><p>$

xi)

$</p><p></p><p>\Rightarrow \quad \left( 1^{-1} + 2^{-1} + 3^{-1} \right) \times 4^{-1} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \left( 1 + \frac{1}{2} + \frac{1}{3} \right) \times \frac{1}{4} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \left( \frac{6 + 3 + 2}{6} \right) \times \frac{1}{4} </p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{11}{6} \times \frac{1}{4}</p><p></p><p>\\ \\</p><p></p><p>\Rightarrow \quad \frac{11}{24}</p><p>$