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Answered by
1
1:a)125 m
b)75 m
2:the maximum displacement of the man will be( 100) root 2..
by using pythagorus.
4:average speed of the bus will 320/8=
=40 m/s
5:
b)75 m
2:the maximum displacement of the man will be( 100) root 2..
by using pythagorus.
4:average speed of the bus will 320/8=
=40 m/s
5:
Answered by
1
4th ans
Average speed =total distance
total time
distance =320km
time =8hours
=320×1000. (1km= 1000m)
9×3600. (1 hour =3600sec)
then ,zeros cut with 1000 with 3600
=3200
288
by cutting of 3200 with 288
Avg. speed =1.1m/s ans
Average speed =total distance
total time
distance =320km
time =8hours
=320×1000. (1km= 1000m)
9×3600. (1 hour =3600sec)
then ,zeros cut with 1000 with 3600
=3200
288
by cutting of 3200 with 288
Avg. speed =1.1m/s ans
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